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Dwaipayan
- Rate Ksh. 2,754
- Response 1h
Ksh. 2,754/hr
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- Maths
- Algebra
- Physics
- Trigonometry
- Geometry
Scientific researcher with a Ph.D. in physics Passionate about teaching physics and mathematics My method : simplify every concept by explaining them from a real-world perspective, focussing on the st
- Maths
- Algebra
- Physics
- Trigonometry
- Geometry
Lesson location
About Dwaipayan
I have recently completed my Ph.D. in physics and have started working as a research scientist. Throughout my student life, I have felt that physics is taught as a scary topic, but it does not have to be that way.In my opinion, it is a very simple subject, that is essentially part of everything in our daily life. I have pursued my education keeping these practical aspects in mind, and I want to help other students do the same.
Besides physics, I love music, soccer, going on long drives and photography trips, and last-but-not-the-least, eating!
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About the lesson
- Lower Primary
- Upper Primary
- Lower Secondary
- +6
levels :
Lower Primary
Upper Primary
Lower Secondary
Tertiary
University
Adult Education
Masters
MBA
Pre-Primary
- English
All languages in which the lesson is available :
English
My main goal is to connect every theory and concept to real-world phenomena. For example, let me try to explain Newton's first and third laws using a very simple example: walking. The laws are as follows :
Law 1 : A body at rest or moving with a constant velocity stays in that state until being acted upon by some net external force.
Law 3 : Every action has its equal and opposite reaction.
Before we begin walking, we are in a standing position, in other words, in a state of rest. From this state, we change to a state of motion. And according to Newton’s law 1, there must be some external force. Where does this force come from?
Lets take a step back and look at law #3 first : Every action has its equal and opposite reaction. In other words, we apply some force on something, that something applies an equal force back.
So, if we apply some force on the ground using our feet, the ground applies a force back. This force essentially is the external force we require to change from our state of rest to state of motion, as described by the 1st law.
Now, let’s say you are walking with a certain constant speed and you want to speed up. What do you do? You apply additional force on the ground. The ground applies the additional force back on you, and you accelerate.
Now, remember, when I stated the first law, I used an expression “net external force”. What did I mean by that?
Let’s say somebody is pushing you from the front or pulling you back as you are trying to walk. Just intuitively, you can tell that you will have to apply more force to walk now. Right?
Let’s now look at it from the physics side of things.
What is going on here is, you have 2 forces being applied ON you (emphasis on the word ON).
1. From the 3rd law , you apply a force on the ground as hence the ground applies an equal force ON you, as we just discussed
2. Whoever is pulling you back, is actually applying a force on you, which is opposite in direction to the force the ground is applying.
So, if these two forces are equal, you have no net force acting on you right? Result : you don’t move.
Now, if you apply slightly more force on the ground as a result of which, the ground will apply slightly more force on you, you have a net force acting on you in the forward direction.
Therefore you will move forward.
I always try to find some example that the students can connect to and explain even the most difficult concepts using this example. I believe this sets me apart as a teacher. My aim is to make physics and mathematics understandable and easy for students of all ages, from middle school to undergraduates.
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- Ksh. 2,754
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- 5h: Ksh. 10
- 10h: Ksh. 20
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- Ksh. 2,754/h
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