XICHEN's email address and phone number have been validated.
XICHEN
- Rate Ksh. 1,905
- Response 4h
-
Students3
Number of students XICHEN has accompanied since arriving at Superprof
Number of students XICHEN has accompanied since arriving at Superprof
Ksh. 1,905/hr
See Maths tutors
Unfortunately, this tutor is unavailable
- Maths
- Algebra
- Geometry
- Statistics
Mathematics student offering maths (including Geometry, Algebra, Statistics etc.) lessons up to first year university level in Bristol
- Maths
- Algebra
- Geometry
- Statistics
Lesson location
About XICHEN
I am a second year student in University of Bristol majoring in maths. Two and a half years of university study has given me good mathematical derivation and computing skills. In the summer of 2018, as a maths tutor, in a half-year part-time teaching, I helped a boy with difficulty learning mathematics effectively improve his mathematical ability and made him interested in mathematics. In this teaching, I used some examples from real life to explain abstract mathematical problems (such as the relationship between geometry and algebra), and cooperated with certain homework exercises and encouragement, step by step, finally effectively improved his confidence in learning mathematics.
See more
About the lesson
- Lower Primary
- Upper Primary
- Lower Secondary
- +6
levels :
Lower Primary
Upper Primary
Lower Secondary
Senior School
Tertiary
Adult Education
Masters
Diploma
Doctorate
- English
All languages in which the lesson is available :
English
Feel relaxed about maths! Sometimes you feel puzzled because you think mathematical problems in a bit complicated way. A tricky example (for junior high school students): How to solve [1/(1*2)]+[1/(2*3)]+...+[1/(99*100)]. Of course you can compute it directly but it is wiser to do in this way: Since 1/(1*2)=(1/1)-(1/2), 1/(2*3)=(1/2)-(1/3), ... ,1/(99*100)=(1/99)-(1/100), the previous fomula = (1/1)-(1/2)+(1/2)-(1/3)+...+(1/98)-(1/99)+(1/99)-(1/100) = 1-(1/100)=99/100. See! You have solved it. For mathematics, I will teach you how to find "the most general description" of a maths problem. Please think about this question: how to solve k/[m*(m+n)]+k/[(m+n)*(m+2n)]+...+k/[(m+(t-1)n)*(m+tn)], where t is a positive integer and all k,m,n are rational numbers! (This is what I said "the most general description")
See more
Rates
Rate
- Ksh. 1,905
Pack prices
- 5h: Ksh. 5
- 10h: Ksh. 10
online
- Ksh. 1,905/h
Details
I don't need tariffs but if possible, I recommend students to come to my college dormitory since it is better to learn maths face to face.
Similar Maths teachers in Bristol
Gladys
Kitui & Online
- Ksh. 800/h
- 1st lesson free
Sir James
Nairobi & Online
- Ksh. 2,000/h
- 1st lesson free
Rophin
Ongata Rongai & Online
- Ksh. 2,000/h
- 1st lesson free
Karanja
Kahawa Sukari & Online
- Ksh. 2,500/h
- 1st lesson free
Purvi
Nakuru & Online
- Ksh. 1,500/h
- 1st lesson free
Evelyn
Nairobi & Online
- Ksh. 1,500/h
- 1st lesson free
Joan
Kiserian & Online
- Ksh. 1,200/h
- 1st lesson free
Mariam
Kisumu & Online
- Ksh. 2,000/h
- 1st lesson free
Amos
Kakamega & Online
- Ksh. 600/h
- 1st lesson free
Arwa
Mombasa & Online
- Ksh. 1,200/h
- 1st lesson free
Edward
Suna & Online
- Ksh. 1,000/h
- 1st lesson free
Margaret
Kiambu & Online
- Ksh. 2,500/h
- 1st lesson free
IVINNE
Nairobi & Online
- Ksh. 500/h
- 1st lesson free
Hudson
Kakamega & Online
- Ksh. 800/h
- 1st lesson free
Ometur
Amagoro & Online
- Ksh. 1,000/h
- 1st lesson free
Blessing
Nairobi & Online
- Ksh. 800/h
- 1st lesson free
SAMUEL
Homa Bay & Online
- Ksh. 900/h
- 1st lesson free
Linet
Kamulu & Online
- Ksh. 500/h
- 1st lesson free
TEACHER GEORGE
Nairobi & Online
- Ksh. 800/h
- 1st lesson free
Nicholas Kimathi
Nairobi & Online
- Ksh. 1,500/h
- 1st lesson free
-
See Maths tutors
